Answer:
x = -2 and x = -10
Step-by-step explanation:
[tex]F(x)=x^2+12x+20\\\\\text{The zeros:}\\\\F(x)=0\iff x^2+12x+20=0\\\\x^2+2x+10x+20=0\\\\x(x+2)+10(x+2)=0\\\\(x+2)(x+10)=0\iff x+2=0\ \vee\ x+10=0\\\\x+2=0\qquad\text{subtract 2 from both sides}\\\boxed{x=-2}\\\\x+10=0\qquad\text{subtract 10 from both sides}\\\boxed{x=-10}[/tex]
