Answer : The molality of the solution is, 0.788 mole/Kg
Solution : Given,
Mass of solute, [tex]I_2[/tex] = 25 g
Mass of solvent, [tex]C_2H_5OH[/tex] = 125 g
Molar mass of solute, [tex]I_2[/tex] = 253.8 g/mole
Molality : It is defined as the number of moles of solute present in one kilogram of solvent.
Formula used :
[tex]Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}[/tex]
Now put all the given values in this formula, we get the molality of the solution.
[tex]Molality=\frac{25g\times 1000}{253.8g/mole\times 125g}=0.788mole/Kg[/tex]
Therefore, the molality of the solution is, 0.788 mole/Kg
