A 5.00 l sample of a gas exerts a pressure of 1040 torr at 50.0°c. In what volume would the same sample exert a pressure of 1.00 atm at 50.0°c?

Respuesta :

Answer: 7L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=1040torr=1.4atm(1torr=0.0013atm)\\V_1=5.00L\\P_2=1atm\\V_2=?[/tex]

Putting values in above equation, we get:

[tex]1.4\times 5.0L=1atm\times V_2\\\\V_2=7L[/tex]

The volume would be 7L at pressure of 1.00 atm at 50.0°C.

The new volume in which the same sample of gas will exert a pressure of 1 atm is 6.84 L

Data obtained from the question

  • Initial volume (V₁) = 5 L
  • Initial pressure (P₁) = 1040 torr
  • Temperature = 50° C = constant
  • New pressure (P₂) = 1 atm = 760 torr
  • New volume (V₂) =?

How to determine the new volume

The new volume of the gas can be obtained by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

1040 × 5 = 760 × V₂

Divide both side by 760

V₂ = (1040 × 5) / 760

V₂ = 6.84 L

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