Respuesta :

Answer:

Period of the given harmonic function is 1.

Step-by-step explanation:

In any harmonic function which is in the form of y = asin(bx+c) + d , we know

Period of this function will be represented as P = [tex]\frac{2\pi }{B}[/tex]

Therefore for the given function d = 5 sin (2πt) we know the value of B is 2π.

So the period will be P = [tex]\frac{2\pi }{2\pi } = 1[/tex]

The answer is period = 1