Respuesta :
we just need make inside square 0
x+10=0
x=-10
y-8=0
y=8
so the center is (-10,8)
Answer:
the center of the circle is (-10,8)
Third option is correct.
Step-by-step explanation:
The equation of the circle is [tex](x+10)^2+(y-8)^2=17[/tex]
This equation can be rewritten as
[tex](x-(-10))^2+(y-8)^2=17[/tex]
The standard form of the circle is given by
[tex](x-h)^2+(y-k)^2=r^2[/tex], where (h,k) is the center of the circle.
On comparing the given equation of circle with the standard form
h = -10, k = 8
Hence, the center of the circle is (-10,8)
Third option is correct.