Determine the domain of the function
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Answer:
Option B is correct.
The domain of the function h(x) is: [tex]\{x | x\neq \pm 6 , x\neq 0\}[/tex]
Step-by-step explanation:
Domain states that the complete set of all the possible values of the independent variable where function is defined.
Given the function:
[tex]h(x) = \frac{9x}{x(x^2-36)}[/tex]
To find the excluded value in the domain of the function.
equate the denominator to 0 and solve for x.
i.e
[tex]x(x^2-36) = 0[/tex]
⇒x = 0 and [tex]x^2-36 = 0[/tex]
⇒x = 0 and [tex]x^2 = 36[/tex]
or
x = 0 and [tex]x = \pm 6[/tex]
So, the domain of the function h(x) is the set of all real number except x = 0 and [tex]x = \pm 6[/tex]
Therefore, the domain of the function h(x) is:
[tex]\{x | x\neq \pm 6 , x\neq 0\}[/tex]
Answer:
Choice b is correct.
Step-by-step explanation:
We have to find the domain of the given function.
The given function is 9x/x(x²-36).
Domain is the all possible values of x for which the function is defined.
so the function is undefined when x(x²-36) = 0.
So,
x(x²-36) =0
either x = 0 or (x² -36) =0
x=0 or x²= 36
x=0 or x = ±6
So, the domain of function is the set of real numbers except x=0 and x = ±6.