Answer:
x=-5, x=7
Step-by-step explanation:
We have the quadratic equations,
[tex]2x^2+5x=x^2+7x+35[/tex]
We can rewrite this equation as
[tex]2x^2-x^2+5x-7x-35=0\\\\x^2-2x-35=0[/tex]
We can solve for x using AC method.
AC = -35
B = -2
The factor pairs of 35 are
1×35, 7×5
Among these two, when we subtract 7 form 5, we get the middle term -2
Hence, -2x=-7x+5x
[tex]x^2-7x+5x-35=0\\\\\text{Take GCF}\\\\x(x-7)+5(x-7)=0\\\\\text{Factor out the common terms}\\\\(x-7)(x+5)=0\\\\x=-5,7[/tex]
Thus, the roots are -5 and 7
