The grams of bicarbonate that will produce 40 ml of CO2 is 0.10007 grams
The dissociation of bicarbonate ion to CO2 can be expressed as:
[tex]\mathbf{HCO^-_3 + H^+ \to H_2CO_3 \rightarrow CO_2 + H_2O}[/tex]
Given that:
At standard conditions:
Using the ideal gas equation;
the number of moles of CO2 can be computed as:
[tex]\mathbf{n = \dfrac{1 \ atm \times 0.04 \ L }{0.0821 \ L.atm/mol.K \times 298 K}}[/tex]
n = 0.00164 moles
The number of grams of bicarbonate produced from 40 mL of CO2 will be:
= 0.00164 moles × 61.0168 g/mol (molar mass of bicarbonate ion)
= 0.10007 grams of bicarbonate ion
Therefore, we can conclude that the grams of bicarbonate that will produce 40 ml of CO2 is 0.10007 grams.
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