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PLEASE HELP!! A.S.A.P!!

The Pythagorean Theorem,
Right triangles Trigonometry

What is the value of X? Leave your answer in simplest Radical form

A.)
[tex] 2\sqrt{5} [/tex]

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B.)
[tex] \sqrt{6} [/tex]

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C.)
[tex] \sqrt{10} [/tex]


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D.)
[tex] 5\sqrt{2} [/tex]

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PLEASE HELP ASAP The Pythagorean Theorem Right triangles TrigonometryWhat is the value of X Leave your answer in simplest Radical formA tex 2sqrt5 tex B tex sqr class=

Respuesta :

gmany

Answer:

[tex]\large\boxed{A.)\ 2\sqrt5}[/tex]

Step-by-step explanation:

The Pythagorean theorem:

[tex]leg^2+leg^2=hypotenuse^2[/tex]

We have

[tex]\leg=2\\leg=4\\hypotenuse=x[/tex]

Substitute:

[tex]x^2=2^2+4^2\\\\x^2=4+16\\\\x^2=20\to x=\sqrt{20}\\\\x=\sqrt{4\cdot5}\\\\x=\sqrt4\cdot\sqrt5\\\\x=2\sqrt5[/tex]

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