Answer:
26pi
Step-by-step explanation:
We are given a region satisfied by the equation as
[tex]x^2 + y^2 <= 4x + 6y+13[/tex]
Rewrite this on left side and use completion of squares method
[tex]x^2-4x+y^2-6y-13\leq 0\\(x-2)^2+(y-3)^2\leq 26[/tex]
Thus the region is the interior of a cricle with centre at (2,3) and radius = square root of 26
Hence area = area of a circle
=[tex]\pi r^2 =26\pi[/tex]
