Respuesta :
Answer:
Step-by-step explanation:
The graph is symmetric with respect to the origin therefore it is on odd function. The graph is symmetric to the y- axis therefore it is an even function. The majority of functions are neither odd nor even, however, sine and tangent are odd functions and cosine is an even function.
The given function y= sin x+1 is neither odd nor even.
What is a function?
- The function(f(x)) is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
- An even function is one that satisfies f(-x) = f(x) for all 'x' in its domain.
- An odd function is one that satisfies f(-x) = -f(x) for all 'x' in its domain.
Why y = sinx+1 is neither odd nor even?
The given function is, f(x)= sinx+1
Let us take [tex]x =\frac{\pi}{2}[/tex]
Substitute this in the given equation,
That is,
[tex]f(x)=1+ sin(\frac{\pi }{2}) \\[/tex]
f(x) = 1+1
f(x) = 2
[tex]f(-x)=1+ sin(-\frac{\pi }{2}) \\[/tex]
f(-x) = 1-1
f(-x) = 0
Here f(-x) ≠ -f(x) and f(-x) ≠ f(x)
Therefore, the given function y= sin x+1 is neither odd nor even.
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