Answer:
The distance between these two given points is:
[tex]3\sqrt{2}[/tex]
Step-by-step explanation:
We are given two points:
(-3,7),(0,4)
The distance between two points (a,b) and (c,d) is given by the distance formula as:
[tex]\sqrt{(c-a)^2+(d-b)^2[/tex]
similarly we can find the length of a line segment by considering the distance between the end points of the line segment.
So here (a,b)=(-3,7)
and (c,d)=(0,4).
Hence distance between these two points is given by:
[tex]\sqrt{(0-(-3))^2+(4-7)^2}=\sqrt{(3)^2+(-3)^2}=\sqrt{9+9}\\ \\=\sqrt{18} \\\\=3\sqrt{2}[/tex]
Answer:
3√2
Step-by-step explanation:
We have given two points and we have to find distance between them.
let (x₁,y₁) = (-3,7) and (x₂,y₂) = (0,4)
d = ?
The formual to find the distence between two points is:
d = √(x₂-x₁)²+(y₂-y₁)²
Putting given values in above formula , we have
d = √(0-(-3))²+(4-7)²
d = √(3)²+(-3)²
d = √9+9
d = √18
d =√2×9
d = 3√2
The distnce between given two points is 3√2.
