Respuesta :
Answer: Amount of iron produced is 101.36 grams.
Explanation:
For the reaction of aluminium and iron oxide, the equation follows:
[tex]2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe[/tex]
By Stoichiometry of the reaction,
When 1 mole of aluminium oxide is produced, then 2 moles of iron is also produced.
So, when 0.905 moles of aluminium oxide is produced, then [tex]\frac{ 2}{1}\times 0.905mol=1.81moles[/tex] of iron is also produced.
Now, to calculate the amount of iron produced, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of iron = 56 g/mol
Moles of iron = 1.81 moles
Putting values in above equation, we get:
[tex]1.81mol=\frac{\text{Mass of iron}}{56g/mol}\\\\\text{Mass of iron produced}=101.36g[/tex]
Hence, amount of iron produced is 101.36 grams.
101.36 gram is the mass of iron produced, if 0.905 mole of Al₂O₃ is produced.
How we calculate the mass using moles?
Mass of any substance can be calculated by using moles as:
n = W/M, where
W = given or required mass
M = molar mass
Given chemical reaction is written as:
2Al + Fe₂O₃ → Al₂O₃ + 2Fe
From the stoichiometry of the reaction:
2 moles of Fe produced = when 1 mole of Al₂O₃ is produced
According to the question:
Produced moles of Al₂O₃ = 0.905 mole
Then produced mole of Fe = 2 × 0.905 mole = 1.81 moles
Now mass of iron can be calculated as:
W = n × M, where
M = molar mass of Fe = 56 g/mole
W = 1.81mole × 56g/mole = 101.36g
Hence, 101.36g is the mass of iron.
To know more about moles, visit the below link:
https://brainly.com/question/3262
