Respuesta :
The molar concentration of O2 is 0.00026 mol/L
Data;
- Pressure = 685 torr
- Temperature = 20°C
- Partial pressure of O2 at sea level = 0.21atm
Convert the pressure from torr to atm
[tex]685torr(\frac{1}{760})=0.901atm[/tex]
The solubility of O2 at 1atm = 1.38*10^-3 mol/L
from the 0.901atm of pressure, 21% is from oxygen
The partial pressure of oxygen = 0.901 * 0.21 = 0.189 atm
Henry' Law
The formula is given as
[tex]S = K_HP\\[/tex]
- S = solubility
- K = Henry's constant
- P = partial pressure
From the formula above,
[tex]\frac{S_1}{S_2} = \frac{P_1}{P_2}[/tex]
substituting the values and solve for the concentration
[tex]\frac{S_1}{S_2}=\frac{P_1}{P_2} \\\frac{1.38^-^3}{S_2}= \frac{1}{0.189} \\ S_2 = 1.38*10^-^3 * 0.189\\S_2 = 0.00026mol/L[/tex]
Therefore, the molar concentration of O2 is 0.00026mol/L
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