Respuesta :
Answer:
The factor form of [tex]4n^2(u+7)-c(u+7)[/tex] is [tex](u+7)[4n^2-c][/tex]
Step-by-step explanation:
Given expression [tex]4n^2(u+7)-c(u+7)[/tex]
We have to factorize the expression ,
Factorization is writing an expression in lowest factor form such that the product of factors gives back the original expression.
Consider given expression [tex]4n^2(u+7)-c(u+7)[/tex]
Taking (u+7) common from both the terms, we get,
[tex]4n^2(u+7)-c(u+7)=(u+7)[4n^2-c][/tex]
Thus the factor form of [tex]4n^2(u+7)-c(u+7)[/tex] is [tex](u+7)[4n^2-c][/tex]