Answer:
Function 2 has a greater initial value
Step-by-step explanation:
An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:
Function1: [tex]y=2x(\frac{1}{3})^x|_{x=0}=2\cdot 0\cdot 1 = 0\\[/tex]
Function2 has value 3 for x=0
So, Function 2 has a greater initial value
