Answer:
The standard form is [tex]-6x^2+11x-4[/tex]
Step-by-step explanation:
Given : [tex](-3x+4)(2x-1)[/tex]
We have to multiply [tex](-3x+4)(2x-1)[/tex]
Consider the given [tex](-3x+4)(2x-1)[/tex]
[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]
Here, a = 3x , b = 4 , c = 2x , d = -1
[tex]=\left(-3x\right)\cdot \:2x+\left(-3x\right)\left(-1\right)+4\cdot \:2x+4\left(-1\right)[/tex]
Apply plus- minus rule, [tex]+\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab[/tex]
[tex]=-3\cdot \:2xx+3\cdot \:1\cdot \:x+4\cdot \:2x-4\cdot \:1[/tex]
Simplify, by adding similar terms, we get,
[tex]=-6x^2+11x-4[/tex]
Thus, The standard form is [tex]-6x^2+11x-4[/tex]
