Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• tanx = [tex]\frac{sinx}{cosx}[/tex]
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
[tex]\frac{tan^2x-sin^2x}{tan^2x}[/tex]
= [tex]\frac{tan^2x}{tan^2x}[/tex] - [tex]\frac{sin^2x}{tan^2x}[/tex]
= 1 - cos²x
= sin²x = right side ⇒ verified