Answer:
Step-by-step explanation:
The resulting course vector (magnitude 300, angle = 160° with the positive x axis (= 290° bearing)) with components (300cos160,300sin160) is the sum of the vector of the actual flight vector and the wind vector.
The wind vector has magnitude 18 and direction 46° with the positive x-axis ( it blows from - 134° with the positive x axis (= 224° bearing) into direction 46° with the positive x-axis). So its components are (18cos46,18sin46).
The course that the plane has to steer is :
(300cos160,300sin160)-(18cos46,18sin46)
=(300cos160 - 18cos46, 300sin160 - 18sin46)
=(-294.41, 89.6579)
The magnitude of this steering vector is = 307.749 knots and its direction will be:
[tex]tan^{-1}=\frac{89.6579}{294.41}=16.94^{{\circ}}[/tex] with the negative x-axis (286.94° bearing).
Thus, the drift angle will be=290° - 286.94° = 3.06°.
