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A gym that is 45 ft long, 30ft wide, and 14ft high , but the four walls and ceiling will be painted. What is the area of the painted part of the gym?

Respuesta :

Answer:

3450 sq. ft

Step-by-step explanation:

1) You will need to find the lateral surface area  (which is the area of the 4 walls) and you will need the area of the ceiling.

2) Use the formula Ph+(l*w) which gives you (150*14)+(30*45).

P is the perimeter of the base, h is the height and you will also need the formula for the area of a rectangle (for the ceiling)

3) The answer will be 3450 sq. ft.

The area of the painted part of the gym is 3450 sq. ft.

  • The calculation is as follows;

Here the formula is used

[tex]= Ph+(l\times w) \\ = (150\times 14)+(30\times 45) [/tex]

= 3,450

Here

P is the perimeter of the base,

h is the height

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