Answer:
A = [tex]\frac{25}{6}[/tex]≈4.17 ft²
Step-by-step explanation:
Even though the problem deals with shapes and area, we can use algebra to solve for the missing area of Square C. Gven the following formulas:
A (square) = s², where s = the measure of one side
A (rectangle) = l x w, where l = length and w = width
We can set up equations to solve for the side length of Square C to find the area. Since the area of Square A = 6 ft²:
A = 6 or 6 = s² so √6 = √s² or s = √6
So, the length of Rectangle B is √6 and the area = 5 ft², so we can solve for 'w', which is also the side length of Square C:
A = 5 ft² or 5 = l x w so 5 = √6w and w = 5/√6
Lastly, find the area of Square C:
A = s² or A = (5/√6)(5/√6) or area = [tex]\frac{25}{6}[/tex]≈4.17 ft²
