Respuesta :
(12xy-9x) -(8y+6). <--group them
(12xy - 9x) (8y - 6). <---- switched the sign infront of the , 6 because of the sign outside its perenthesis
3x(4y -3). 2(4y-3). <--gcf of 12xy and 9x is 3x n divided both by 3x n got that n I did the same steps n got the other
(3x+2) (4y-3)<-- o took the ones outside the parenthesis n had them in one together, n the other ones already in the parenthesis looked the same so I picked one..
ans is (3x+2)(4y-3)
hope I helped :)
(12xy - 9x) (8y - 6). <---- switched the sign infront of the , 6 because of the sign outside its perenthesis
3x(4y -3). 2(4y-3). <--gcf of 12xy and 9x is 3x n divided both by 3x n got that n I did the same steps n got the other
(3x+2) (4y-3)<-- o took the ones outside the parenthesis n had them in one together, n the other ones already in the parenthesis looked the same so I picked one..
ans is (3x+2)(4y-3)
hope I helped :)
Answer:
Given that: [tex]12xy -9x -8y +6[/tex]
To find the factors of the polynomial with two variables.
(1)
First take the common factor from first two terms.
Common factor from first two terms is, 3x
then, it becomes;
[tex]3x(4y-3)[/tex]
(2) Now, again taking the common factor from last two terms.
i,e -2
so, it becomes;
[tex]-2 (4y -3)[/tex]
Then, the combined form of the given polynomial
[tex]12xy -9x -8y +6[/tex] is;
[tex]3x(4y-3)-2(4y-3)[/tex]
[tex](4y-3)(3x-2)[/tex]
Therefore, the completely factored form of [tex]12xy -9x -8y +6[/tex] is, [tex](4y-3)(3x-2)[/tex]