Respuesta :
Molar mass Na = 23.0 g/mol
1 mole Na ------- 23.0 g
? mole Na ------ 0.50 g
moles = 0.50 * 1 / 23.0
moles = 0.50 / 23.0
= 0.0217 moles of Na
Molarity = number of moles / liters solution
M = 0.0217 / 1.5
= 0.014467 M
hope this helps!
1 mole Na ------- 23.0 g
? mole Na ------ 0.50 g
moles = 0.50 * 1 / 23.0
moles = 0.50 / 23.0
= 0.0217 moles of Na
Molarity = number of moles / liters solution
M = 0.0217 / 1.5
= 0.014467 M
hope this helps!
Answer : The molarity of solution is, 0.0145 mole/L
Solution : Given,
Mass of solute, Na= 0.50 g
Volume of solution = 1.5 L
Molar mass of Na= 23 g/mole
Molarity : It is defined as the number of moles of solute present in the one liter of solution.
Formula used :
[tex]Molarity=\frac{w_b}{M_b\times V}[/tex]
where,
[tex]w_b[/tex] = mass of solute, Na
V = volume of solution in liters
[tex]M_b[/tex] = molar mass of solute, Na
Now put all the given values in the above formula, we get the molarity of a solution.
[tex]Molarity=\frac{0.50g}{23g/mole\times 1.5L}=0.0145mole/L[/tex]
Therefore, the molarity of solution is, 0.0145 mole/L