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Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

Respuesta :

Willchemistry
M₁ *V₁ = M₂ * V₂

12.0 * V₁ = 6.0 * 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

hope this helps!

Answer : The volume of concentrated hydrochloric acid is, 0.25 liters

Explanation :

Using neutralization law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L

[tex]M_2[/tex] = molarity of hydrochloric acid = 6 M = 6 mole/L

[tex]V_1[/tex] = volume of concentrated hydrochloric acid = ?

[tex]V_2[/tex] = volume of hydrochloric acid = 500 ml = 0.5 L

Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.

[tex]12mole/L\times V_2=6mole/L\times 0.5L[/tex]

[tex]V_2=0.25L[/tex]

Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters

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