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if i have 7.7 moles of a gas at a pressure of 0.09 ATM and a temperature of 329 K , what is the volume of the container that the gas is in ?

Respuesta :

n=number of moles=7.7 moles.
P=pressure at atm=0.09 atm
T=temperature at ºK=329 ºK
R=universal gas costant=0.082 (L*atm ) / (ºK*mol)

The ideal gas law:

PV=nRT

therefore:
0.09 atm*V=7.7 moles * 0.082 (L*atn)/(ºK* mol) * 329ºK
V=(7.7 moles * 0.082 (L*atn)/(ºK* mol) * 329ºK) / (0.09 atm)=2,308.12 L

Answer: the volume is  2,308.12 litres

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