An investment earning interest at the rate of 10%, compounded continuously, will double in t years. Find t. Use the formula , where is the amount after t years, is the initial amount, r is the rate of interest, and t is the time. t = years.

Respuesta :

Answer:

I have attached the formula solved for years (or time).

We'll say principal = 100 and total = 200

Years = ln (200 / 100) / .1

Years = ln (2) / .1

Years = 0.69314718056 / .1

Years = 6.9314718056


Step-by-step explanation:


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The time will be equal to 6.9 years when compounded continuously.

What is compound interest?

Compound interest is the interest levied on the interest. It is given in the question that an investment earning interest at the rate of 10%, compounded continuously, will double in t years.

We are having the following data:-

principal = 100 and

total = 200

The time will be calculated by using the formula below:-

[tex]t = In[\dfrac{Total}{Principle}] / Rate[/tex]

[tex]Years = [ln (\dfrac{200} { 100} ]/ .1[/tex]

[tex]t = \dfrac{ln (2)} { 0.1}[/tex]

t = 0.69314718056 / .1

t = 6.93 years

Therefore the time will be equal to 6.9 years when compounded continuously.

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