Point E is located at (−1, 6) and point F is located at (3, 9)

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What are the coordinates of the point that partitions the directed line segment EF¯¯¯¯¯ in a 3:2 ratio?



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Respuesta :

Answer:

The required coordinates are [tex](\frac{7}{5},\frac{39}{5})[/tex].

Step-by-step explanation:

Let the new point be P.

If a point divide a line in m:n, then the coordinates of point are

[tex](\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex]

If is given that Point E is located at (−1, 6) and point F is located at (3, 9). Point P divides the line in 3:2. The coordinates of P are

[tex]P=(\frac{3(3)+2(-1)}{3+2},\frac{3(9)+2(6)}{3+2})[/tex]

[tex]P=(\frac{7}{5},\frac{39}{5})[/tex]

Therefore the required coordinates are [tex](\frac{7}{5},\frac{39}{5})[/tex].

Answer:

(1.4,7.8)

Step-by-step explanation:

I took the quiz. I hope this helps :)

Ver imagen LindsayCharlotte06