Answer: 3 moles of water are formed. The limiting reagent is Oxygen atom and the excess reagent is Hydrogen atom.
Explanation:
From the image provided, there are 8 moles of Hydrogen atom and 3 moles of Oxygen atom.
The equation for the formation of water is given by:
[tex]2H+O\rightarrow H_2O[/tex]
By Stoichiometry,
1 mole of Oxygen atom reacts with 2 moles of Hydrogen atom.
So, 3 moles of Oxygen atom will react with = [tex]\frac{2}{1}\times 3=6moles[/tex] of Hydrogen atom.
The required amount of Hydrogen atom is less than the given amount of Hydrogen atom, hence, it is considered as an excess reagent.
Therefore, Oxygen atom is the limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 moles of oxygen atom produces 1 mole of water molecule.
So, 3 moles of oxygen atom will produce = [tex]\frac{1}{1}\times 3=3moles[/tex] of water molecule.
Thus, 3 moles of water are formed. The limiting reagent is Oxygen atom and the excess reagent is Hydrogen atom.
