Answer:
[tex]5 m/s^2[/tex]
Explanation:
The acceleration of the train is given by:
[tex]a=\frac{v-u}{t}[/tex]
where:
u = 5 m/s is the initial velocity of the train
v = 45 m/s is the final velocity of the train
t = 8 s is the time taken for the train to increase the velocity
Substituting numbers into the formula, we find
[tex]a=\frac{45 m/s-5 m/s}{8 s}=5 m/s^2[/tex]
