40 points!! Please help!! need help ASAP!! Will mark Brainliest!!!! and if you can please show your work so that I will know how to do it for future problems that would be great!! Thx!! :)
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A is located at (0,0)
A' is located at (5,2)
Distance (Length) = √((x2-x1)^2 +(y2-y1)^2)
= √(5-0^2) + (2-0^2)
= √5^2 + 2^2
= √25 +4
=√29 ( Exact) or 5.385 as a decimal and round the answer as needed.
The problem doesn't say if the answer was needed as a decimal or not.
Look at the picture.
Use the Pythagorean theorem:
[tex]|AA'|^2=5^2+2^2\\\\|AA'|^2=25+4\\\\|AA'|^2=29\to|AA'|=\sqrt{29}[/tex]
Answer: [tex]\boxed{AA'=\sqrt{29}}[/tex]