Answer:
impulse acting on it
Explanation:
The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied ([tex]\Delta t[/tex]):
[tex]I=F\Delta t[/tex]
We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:
[tex]\Delta p = m \Delta v[/tex]
where m is the mass and [tex]\Delta v[/tex] is the change in velocity. Multiplying and dividing by [tex]\Delta t[/tex], we get
[tex]\Delta p = m \frac{\Delta v}{\Delta t} \Delta t[/tex]
and since [tex]\frac{\Delta v}{\Delta t}[/tex] is equal to the acceleration, a, we have
[tex]\Delta p = ma \Delta t[/tex]
And since the product (ma) is equal to the force, we have
[tex]\Delta p = F \Delta t[/tex]
which corresponds to the impulse.
