Answer:
[tex]\frac{9}{41}[/tex]
Step-by-step explanation:
given cosq = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{9}{41}[/tex]
Then qs = 9 and qr = 41
sin r = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{qs}{qr}[/tex], hence
sin r = [tex]\frac{9}{41}[/tex]
