Answer:
Value of the expression [tex]\frac{20 - (12 + ac)^{2}}{a\times c + 5}[/tex] when a = 2, b = 4, c = -3 is 16 .
Step-by-step explanation:
As the expression given in the question be
[tex]= \frac{20 - (12 + ac)^{2}}{a\times c + 5}[/tex]
Where a = 2 , b =4 , c = -3
Putting all the values in the above
[tex]= \frac{20-(12+2\times -3)^{2}}{2\times -3 + 5}[/tex]
[tex]= \frac{20-(12-6)^{2}}{-6 + 5}[/tex]
[tex]= \frac{20-(12-6)^{2}}{-6 + 5}[/tex]
[tex]= \frac{20-(6)^{2}}{-6 + 5}[/tex]
[tex]= \frac{20-36}{-6 + 5}[/tex]
[tex]= \frac{-16}{-1}[/tex]
= 16
Therefore the value of the expression [tex]\frac{20 - (12 + ac)^{2}}{a\times c + 5}[/tex] when a = 2, b = 4, c = -3 is 16 .
