For this case we have a function of the form [tex]y = f (x)[/tex], where [tex]f (x) = \frac {1} {4} x-2[/tex]
We want to find the value of "x" when the function has the value of -1, that is, when[tex]y = f (x) = - 1[/tex]
So:
[tex]f (x) = \frac {1} {4} x-2 = -1\\\frac {1} {4} x-2 = -1[/tex]
We clear "x":
We add "2" to both sides of the equation:
[tex]\frac {1} {4} x-2 + 2 = -1 + 2\\\frac {1} {4} x = 1[/tex]
We multiply by "4" on both sides of the equation:
[tex]\frac {1} {4} x * 4 = 1 * 4\\x = 4[/tex]
So, when[tex]y = -1[/tex]then [tex]x = 4[/tex]
Answer:
[tex]x = 4[/tex]
