Heather has divided ​$5400 between two​ investments, one paying 8​%, the other paying 5​%. if the return on her investment is ​$345, how much does she have in each​ investment?

Respuesta :

Answer:

$2500 at 8%.

$2900 st 5%.

Step-by-step explanation:

Let x be the amount invested at rate of 8% and y be the amount invested at the rate of 5%.

We have been given that Heather has divided ​$5400 between two​ investments. We can represent this information as:

[tex]x+y=5400...(1)[/tex]

The return on her investment is ​$345.  

Earnings from the investment at 8% will be 8% of x.

Earnings from the investment at 5% will be 5% of y.

[tex](\frac{8}{100})x+(\frac{5}{100})y=345...(2)[/tex]

[tex]0.08x+0.05y=345...(2)[/tex]

We will use substitution method to solve our system of equations. From equation (1) we will get,

[tex]x=5400-y[/tex]

Substituting this value in equation (2) we will get,

[tex]0.08(5400-y)+0.05y=345[/tex]

[tex]432-0.08y+0.05y=345[/tex]

[tex]-0.08y+0.05y=345-432[/tex]

[tex]-0.03y=-87[/tex]

[tex]\frac{-0.03y}{-0.03}=\frac{-87}{-0.03}[/tex]

[tex]y=2900[/tex]  

Therefore, Heather has invested an amount of $2900 at 5%.

Let us substitute y=2900 in equation (1) to solve for x.

[tex]x+2900=5400[/tex]

[tex]x+2900-2900=5400-2900[/tex]

[tex]x=2500[/tex]

Therefore, Heather has invested an amount of $2500 at 8%.