About 5.67811 X10^5 liters of water flow over Niagara Falls per second there are 3.15576 x10^7 seconds in one year the number of liters of water that flows over Niagara Falls each year are about 5.67811 x 10^5 x3.15476x10^7
A.1e12
B. 179187524.1
C.1.791875241e13
D. 1.92559524e-44

Respuesta :

Answer:  C. 1.7918752e+13

Step-by-step explanation:

Since, water flow over Niagara Falls per second = [tex]5.67811 \times 10^5[/tex]

In one year, the number of seconds = [tex]3.15576 \times 10^7[/tex]

Thus, the total quantity of water flows over Niagara Falls each year

= [tex]5.67811 \times 10^5 \times 3.15476\times 10^7[/tex]

= [tex]1.7918752\times 10^{13}[/tex]

= [tex]1.7918752e13[/tex]

Option C is correct.

Answer:

Is c 1.7918752e+13

Step-by-step explanation: