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About 5.67811 X10^5 liters of water flow over Niagara Falls per second there are 3.15576 x10^7 seconds in one year the number of liters of water that flows over Niagara Falls each year are about 5.67811 x 10^5 x3.15476x10^7
A.1e12
B. 179187524.1
C.1.791875241e13
D. 1.92559524e-44

Respuesta :

Answer:

C.  1.791875241e13

Step-by-step explanation:

We have that,

Amount of water flows over Niagara Falls per second = 5.67811×10⁵

Also, the number of seconds in a year = 3.15576×10⁷

Thus,

Liters of water that flows in a year = Amount of water that flows × Number of seconds

i.e. Liters of water = 5.67811 × 10⁵ × 3.15576 × 10⁷

i.e. Liters of water = 17.91875241 × 10¹²

i.e. Liters of water = 1.791875241 × 10¹³

Hence, the liters of water that flows through Niagara Falls each year is 1.791875241 × 10¹³ i.e. 1.791875241e13

Answer:

C-the one with e13

Step-by-step explanation: I just did it on i-ready and got it right. plz mark brainliest.

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