Answer:
The Answer is y= -5x+16.
Step-by-step explanation:
A line that is parallel to another line has to have the same slope.
So start with y= -5x.
Then use the point (3,1) to find the y-intercept.
(1)= -5(3)
1 = -15
then find out what you need to do to the x side to get it to equle the y side in this equation its +16.
so your Answer is y= -5x+16.
The required equation of line is y = -5x + 16.
The general equation of a straight line is
y = mx + c
where m is the slope of line and c is called the intercept on y-axis.
Now the given equation of line is
y= -5x+3
which is of the form y = mx + c
So slope of line m = -5
and intercept c = 3
To find the equation of line parallel to the line of the given equation and passes through point (3,1).
Since both the lines are parallel to each other,
Applying slope relationship between perpendicular lines.
m₁ = m₂ = m
where m₁ and m₂are slopes of parallel lines.
⇒ m₂ = -5
Since line passes through the point (3,1) i.e (x₁ , y₁ )
Therefore he required equation of is given as,
(y-y₁ ) = m(x-x₁)
Putting the values we get
(y-1 ) = -5(x-3)
⇒y = -5x + 15 + 1
⇒y = -5x + 16
Hence the required equation of line is y = -5x + 16.
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