25,000 Feet = 7620m
PE = mgh where m is mass, g is gravity accel: 9.8 n h is height
= 90 x 9.8 x 7620
= 6720840J
= 6.72MJ
F = ma where m is mass, a is accel = gravity = 9.8
= 90 x 9.8
= 882N
Accel = gravity = 9.8m/s^2
KE = 1/2mv^2 where m is mass n v is vel
if no wind resistance, PE leaving airplane = KE at net
6720840 = 1/2 x 90 x v^2
v^2 = 149352
v = 386.5m/s
This is a fun question - your science teacher is creative!
First is easy, 25000 feet converts to 7620 meters
Potential energy is a product of mass, gravity and height. In this case, mass is 90Kg and height is 7620m. gravity on earth is 9.8m/s2.
Potential energy = 90(9.8)(7620) = 6720840J
By Newton 2nd law, force is equal to mass times acceleration.
Gravity force = mass*gravity
= 90(9.8) = 882N
Acceleration when he leaves the plane is gravity, 9.8m/s2
With no wind resistance, the acceleration is constant at 9.8.
Using kinematic equation, v2 = u2 + 2as where u is initial velocity, v is final velocity, a is acceleration and s is distance traveled.
In this case, u=0, a=9.8, s=7620
v^2 = 2(9.8)(762) = 149352
final velocity = sqrt (149352) = 386.5m/s
