Respuesta :
Answer: The heat required will be 58.604 kJ.
Explanation:
To calculate the amount of heat required, we use the formula:
[tex]Q= m\times c\times \Delta T[/tex]
Q= heat gained or absorbed = ? J
m = mass of the substance = 100 g
c = heat capacity of water = 4.186 J/g ° C
Putting values in above equation, we get:
[tex]\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC[/tex]
[tex]Q=100g\times 4.186J/g^oC\times 140^oC[/tex]
Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)
Thus, heat released by 100 grams of ice is 58.604kJ.
