The slope-intercept form:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept.
From equations that have a choice we have y-intercept
[tex]b=-\dfrac{13}{3}[/tex]
We haave the point (-5, -1). Put the coordinates of the point to the equation of a line:
[tex]y=mx-\dfrac{13}{3}[/tex]
[tex]-1=-5m-\dfrac{13}{3}[/tex] multiply both sides by 3
[tex]-3=-15m-13[/tex] add 13 to both sides
[tex]10=-15m[/tex] divide both sides by (-15)
[tex]m=-\dfrac{10}{15}\\\\m=-\dfrac{10:5}{15:5}\\\\m=-\dfrac{2}{3}[/tex]
Answer: [tex]\boxed{y=-\dfrac{2}{3}x-\dfrac{13}{3}}[/tex]
