Respuesta :
The weight/weight % or percent by mass of the solute is 5.41%
Given:
Mass of the sodium sulfate, [tex]w = 9.74g[/tex]
Volume of the water [tex]= 165 mL[/tex]
Density of the water [tex]= 1 g/mL[/tex]
Explanation:
Mass of the water [tex]= 1 g/mL X 165 mL[/tex]
[tex]= 165 g[/tex]
Mass of the solution w = Mass of solute + Mass of solvent
[tex]w =9.47 g + 165 g[/tex]
[tex]=174.47 g[/tex]
[tex]\frac{W}{w}[/tex] %=[tex]\frac{W}{w}[/tex]×100w
[tex]=\frac{45g}{9}[/tex]×[tex]100174g[/tex]
[tex]=5.41%[/tex]%
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