Answer:
(Segment JL)(Segment ML)=10(6.4)=64 units
Step-by-step explanation:
In the given information, triangle JKL with right angle at K. Segment JK is 6 and segment KL is 8. Point M is on segment JL and angles KMJ and KML are right angles.
we have to choose the correct option.
In order to choose we have to find the segment ML
Let ML=x therefore JM=10-m
In triangle JMK, by Pythagoras theorem
[tex]JK^{2}=JM^{2}+MK^{2}\\ 36=(10-m)^2+KM^2\\KM^2=36-(10-m)^2[/tex]
In triangle KML
[tex]KL^{2}=KM^{2}+ML^{2}\\ 64=m^2+KM^2\\KM^2=64-m^2[/tex]
From above two equations we get
[tex]36-(10-m)^2=64-m^2[/tex]
⇒ [tex]64-m^2=36-(10-m)^2[/tex]
⇒ [tex]20m=\frac{128}{20}[/tex]
⇒ m=6.4 units
(Segment JL)(Segment ML)=10(6.4)=64 units
Hence, last option is correct
Answer:
Segment JL × segment JM = 36
Segment JL × segment LM = 64
Step-by-step explanation:
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