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Part A
A business purchases a computer system for $3,000. The value of the system decreases at a rate of 15% per year. Which exponential function models this situation?

A. f(x) = 3,000(0.15)x
B. f(x) = 3,000(0.85)x
C. f(x) = 3,000 – 0.15x
D. f(x) = 3,000 – 0.85x
Part B
The function f(x) = 3,000(0.85)x models the value of a computer system. Find the value of the computer after 4 years.

Value after 4 years = $ ____

Respuesta :

sqdancefan

Answer:

  • B. f(x) = 3,000(0.85)^x
  • $1566.02

Step-by-step explanation:

Part A

At the end of the year, the value of the computer system is ...

... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)

... = 0.85 · (beginning value)

Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...

... f(x) = (beginning value) · 0.85^x

The beginning value is given as $3000, so this is ...

... f(x) = 3000·0.85^x

____

Part B

For x=4, this is ...

... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02

The value after 4 years is $1566.02.

The exponential function that models this situation will be:

  • f(x) = 3,000(0.85)x

From the information given, the function f(x) = 3,000(0.85)x models the value of a computer system, the value of the computer after 4 years will be:

= f(x) = 3,000(0.85)x

= f(x) = 3,000(0.85)⁴

= 1566.02.

Therefore, the value of the computer after 4 years will be $1566.02.

Learn more about equations on:

https://brainly.com/question/13763238

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