Answer: Current offered by the car battery is 8 times the current offered by the batteries in the flash lights.
I' = 8 × I
Explanation:
Voltage used in flash lights ,V = 1.5 Volts
Current offered by the V = I
[tex]V=IR[/tex]...(1)
Voltage used in car battery,V' = 12 Volts
Current offered by the V' = I'
[tex]V'=I'R'[/tex]..(2)
Dividing (2) and (1)
[tex]\frac{V'}{V}=\frac{I'R'}{IR}=\frac{I'R}{IR}=\frac{I'}{I}[/tex]
(Given that resistance offered by both is same,R'=R)
[tex]\frac{12 volts}{1.5 volts}=\frac{I'}{I}[/tex]
I' = 8 × I
Current offered by the car battery is 8 times the current offered by the batteries in the flash lights.
