Respuesta :

harpazo

Let a = given base


Let b = the other base


Let h = height


A = (1/2)(a + b)h


60 = (1/2)(4 + b)(12)


We now solve for b.


60 = 6(4 + b)


60 = 24 + 6b


60 - 24 = 6b


36 = 6b


36/6 = b


6 = b


The other base measures 6 feet.


Answer:

B

Step-by-step explanation:

the area of a trapezoid (A) is calculated using the formula

A = [tex]\frac{1}{2}[/tex] h(a + b)

where h is the height and a, b the parallel sides

here h = 12, a = 4 and A = 60, hence

[tex]\frac{1}{2}[/tex] × 12(4 + b) = 60

6(4 + b) = 60 ( divide both sides by 6 )

4 + b = 10 ( subtract 4 from both sides )

b = 6

Hence the other base = 6 ft → B


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