Respuesta :
Answer: Option (d) is the correct answer.
Explanation:
Electronegativity value of hydrogen is 2.2.
Electronegativity value of chlorine is 3.16.
Electronegativity value of carbon is 2.55.
Electronegativity value of oxygen is 3.44.
Electronegativity value of nitrogen is 3.04.
Electronegativity value of sodium is 0.93.
Electronegativity value of iodine is 2.66.
Therefore, calculate the electronegativity difference between the bonded atoms as follows.
- Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen
= 3.16 - 2.2
= 0.96
- Electronegativity difference of CO = Electronegativity value of oxygen - electronegativity value of carbon
= 3.44 - 2.55
= 0.89
- Electronegativity difference of [tex]N_{2}[/tex] = Electronegativity value of nitrogen - electronegativity value of nitrogen
= 3.04 - 3.04
= 0
- Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium
= 2.66 - 0.93
= 1.73
So, we can see that highest electronegativity difference is 1.73 and it is shown by NaI molecule.
Thus, we can conclude that a group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms.
Which of the following has the greatest electronegativity difference between the bonded atoms? d. A group 1 alkali metal bonded to iodide, such as NaI.
Further explanation
Electronegativity with the symbol χ is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.
- Electronegativity value of hydrogen is 2.2.
- Electronegativity value of chlorine is 3.16.
- Electronegativity value of carbon is 2.55.
- Electronegativity value of oxygen is 3.44.
- Electronegativity value of nitrogen is 3.04.
- Electronegativity value of sodium is 0.93.
- Electronegativity value of iodine is 2.66.
Therefore, the electronegativity difference between the bonded atoms are:
Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen =[tex]3.16 - 2.2 = 0.96[/tex]
Electronegativity difference of Co = Electronegativity value of oxygen - electronegativity value of carbon [tex]= 3.44 - 2.55 = 0.89[/tex]
Electronegativity difference of [tex]n_{2}[/tex] = Electronegativity value of nitrogen - electronegativity value of nitrogen [tex]= 3.04 - 3.04 = 0[/tex]
Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium [tex]= 2.66 - 0.93 = 1.73[/tex]
Therefore, we can see that highest electronegativity difference is [tex]1.73[/tex] and it is shown by NaI molecule.
Sodium iodide (chemical formula NaI) is an ionic compound formed from the chemical reaction of sodium metal and iodine.
Therefore, we can conclude that a group 1 alkali metal bonded to iodide, such as naI has the greatest electronegativity difference between the bonded atoms.
Learn more
- Learn more about electronegativity https://brainly.com/question/899245
- Learn more about hydrogen https://brainly.com/question/10799430
- Learn more about halogen https://brainly.com/question/1380547
Answer details
Grade: 9
Subject: chemistry
Chapter: electronegativity
Keywords: electronegativity, hydrogen, halogen, strong acid, Carbon
