1. You are correct. Slope is a line's rise over its run. This line goes down 2 units for every one unit right.
2. Building off of this, you can see that for this problem, the line goes up 1 unit every 2 units right, making your slope 1/2.
3. This is a bit more confusing than the last two, so you can find the slope of the line using the slope formula. In this case, I will be using points (-5,-2) and (5,5). Slope formula is [tex]\frac{y2-y1}{x2-x1}[/tex]. This becomes [tex]\frac{5-(-2)}{5-(-5)}[/tex] which is [tex]\frac{7}{10}[/tex].
4. Using the points (-5,4) and (5,-4): [tex]\frac{-4-4}{5-(-5)}[/tex]. This is [tex]-\frac{8}{10}[/tex] and -4/5 in simplest form.
5. The line goes down 5 units every one unit to the right. Because it goes down, our slope is -5.
6. The line goes up 5 units every time it moves right once. The slope is the same as #5 except for the fact that it's positive, so it goes up.
7. The line goes down one unit every 5 units to the right, making our slope [tex]-\frac{1}{5}[/tex].
8. The line goes down 4 units every 2 units to the right, which is -4/2, although I would recommend writing it as -2.
