In a race, Bethany is located ​ −60 1/2 ​ meters relative to her friend, Monica, after 2 1/5 minutes. Assuming both girls are running at a constant rate, what was Bethany's location relative to Monica's after 1 minute? Enter your answer as a mixed number, in simplest form, in the box.

Respuesta :

Answer: Bethany's location relative to Monica's after 1 minute is [tex]27\frac{1}{2}\ meters[/tex]

Step-by-step explanation:

Since we have given that

After [tex]2\frac{1}{5}\ minutes=\frac{11}{5}\ minutes[/tex],

Distance between Bethany is located relative to her friend is given by

[tex]60\frac{1}{2}\ meters\\\\=\frac{121}{2}\ meters[/tex]

We need to find the distance between Bethany's location relative to Monica's after 1 minute.

We will use "Unitary Method":

After [tex]\frac{11}{5}\ minutes[/tex],

[tex]Distance=\frac{121}{2}\ meters[/tex]

After 1 minute,

[tex]Distance=\frac{\frac{121}{2}}{\frac{11}{5}}\\\\Distance=\frac{121\times 5}{11\times 2}\\\\Distance=\frac{55}{2}\ meters\\\\Distance=27\frac{1}{2}\ meters[/tex]

Hence, Bethany's location relative to Monica's after 1 minute is [tex]27\frac{1}{2}\ meters[/tex]