Answer:
10 9 8 7
Step-by-step explanation:
There are 10 choices for the first digit,
9 choices for the second digit,
8 choices for the third digit, and
7 choices for the fourth digit.
Using the fundamental counting principle, how many access codes are possible? 5,040
If the digits 0 through 9 could be repeated, how many access codes would be possible? 10,000
The number of ways for the security of cars will be 5040.
A permutation is an act of arranging items or elements in the correct order.
The access code for a car’s security system consists of four digits, 0 through 9.
Once a digit is used, it cannot be repeated.
There are choices for the first digit, choices for the second digit, choices for the third digit, and choices for the fourth digit.
Then the number of ways for the security of car will be
¹⁰P₄ = [10! / (10 - 4)!]
¹⁰P₄ = [10 x 9 x 8 x 7 x 6! / 6!]
¹⁰P₄ = 10 x 9 x 8 x 7
¹⁰P₄ = 5040
More about the permutation link is given below.
https://brainly.com/question/11732255
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